#### 48.5


Let the scores be \( a, a+d, a+2d, a+3d, a+4d \), where \( a = 65 \) and \( a+4d = 89 \).
Solve for \( d \):
a + 4d = 89 \\
+ 4d = 89 \\
4d = 24 \\
d = 6
The scores are: 65, 71, 77, 83, 89.
The average score is the sum divided by 5:
\text{Average} = \frac{65 + 71 + 77 + 83 + 89}{5} = \frac{385}{5} = 77
#### 77