= 3 - 6i + 4i - 8i^2

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• z_1 \cdot z_2 = (3 + 4i)(1 - 2i)
• Expanding this, we get:
• = 3 \cdot 1 + 3 \cdot (-2i) + 4i \cdot 1 + 4i \cdot (-2i)
• Recall that \(i^2 = -1\). Substituting, we have:
• = 3 - 6i + 4i + 8
• = (3 + 8) + (-6i + 4i)

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