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February 22, 2026
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\( a_3 = 2(5) + 3 = 13 \)
\( a_4 = 2(13) + 3 = 29 \)
\( a_5 = 2(29) + 3 = 61 \)
\[ x^2 - 4x + 3 = 0 \]
\[ (x - 1)(x - 3) = 0 \]
Solutions: \( x = 1 \) or \( x = 3 \).
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