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eq -2 $, we can cancel $ t + 2 $:
S(t) = t + 3
Now, we are to find the smallest integer value of $ t $ such that $ S(t) $ is an integer. Since $ S(t) = t + 3 $ for all $ t
eq -2 $, and $ t + 3 $ is always an integer when $ t $ is an integer (except at $ t = -2 $, where the function is undefined), the smallest integer $ t $ for which $ S(t) $ is defined and an integer is the smallest integer greater than $-2$, which is $ t = -1 $.
Evaluate $ S(-1) $:
S(-1) = -1 + 3 = 2
Hence
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