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/ ot\in \mathbb{Z}
ot\in \mathbb{Z}
February 22, 2026
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Points: \((0, 2), (0, -2)\)
\(x = \pm 1\):
rac{1}{9} + rac{y^2}{4} = 1 \Rightarrow rac{y^2}{4} = rac{8}{9} \Rightarrow y^2 = rac{32}{9}
No solutions.
\(x = \pm 2\):
rac{4}{9} + rac{y^2}{4} = 1 \Rightarrow rac{y^2}{4} = rac{5}{9} \Rightarrow y^2 = rac{20}{9}
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