P = 6 \times s
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- A regular hexagon is inscribed in a circle with a radius of \(10\) cm. If each side of the hexagon is increased by \(2\) cm, what is the new perimeter of the hexagon? Express your answer in terms of the circle’s radius.
- A regular hexagon inscribed in a circle has side lengths equal to the radius of the circle. Therefore, the original side length \(s\) of the hexagon is equal to the radius of the circle, which is \(10\) cm. The perimeter \(P\) of a regular hexagon is given by:
- For the original hexagon, the perimeter is:
- P = 6 \times 10 = 60 \text{ cm}
- If each side is increased by \(2\) cm, the new side length becomes:
