t = \frac{4 \pm 2}{6}
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- t = \frac{-(-4) \pm \sqrt{(-4)^2 - 4 \cdot 3 \cdot 1}}{2 \cdot 3}
- t = \frac{4 \pm \sqrt{16 - 12}}{6}
- t = \frac{4 \pm \sqrt{4}}{6}
- t = \frac{6}{6} = 1 \quad \text{and} \quad t = \frac{2}{6} = \frac{1}{3}
- Both values satisfy the equation. Thus, the values of \(t\) are:
- \boxed{1 \quad \text{and} \quad \frac{1}{3}}
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