Take natural logarithm:

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• 2e^{0.3t} > 40
• Divide both sides by 2:
• e^{0.3t} > 20
• 0.3t > \ln(20) \approx 2.9957
• t > \frac{2.9957}{0.3} \approx 9.9857
• The smallest integer greater than 9.9857 is \(t = 10\).

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