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n_1 \sin(\theta_1) = n_2 \sin(\theta_2)
where \( n_1 = 1.00 \), \( \theta_1 = 30^\circ \), and \( n_2 = 1.50 \).
Plug in the known values:
\times \sin(30^\circ) = 1.50 \times \sin(\theta_2)
= 1.50 \times \sin(\theta_2)
Solve for \(\sin(\theta_2)\):
\sin(\theta_2) = \frac{0.5}{1.50} = \frac{1}{3} \approx 0.3333
Find the angle of refraction \(\theta_2\) by taking the inverse sine:
\theta_2 = \sin^{-1}(0.3333) \approx 19.47^\circ
#### 19.47